Guys please solve this question quickly, I don't understand this
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1
x = 7+4√3
x = 4+3+4√3
x = 2^2 +√3^2 + 4√3
Now,
x = (2+√3)^2
Taking square root on both sides
√x = +- 2+√3
Now,
√x+1/√x
= x + 1. / √x
= 7+4√3 + 1 /2+√3
= 8+4√3 / 2+√3
then rationalise this
Similarly
= 7+4√3 +1/-2-√3
and rationalise this
x = 4+3+4√3
x = 2^2 +√3^2 + 4√3
Now,
x = (2+√3)^2
Taking square root on both sides
√x = +- 2+√3
Now,
√x+1/√x
= x + 1. / √x
= 7+4√3 + 1 /2+√3
= 8+4√3 / 2+√3
then rationalise this
Similarly
= 7+4√3 +1/-2-√3
and rationalise this
Answered by
2
First of all, notice that
7 + 4 sqrt(3)
= 4 + 2 sqrt(3) + 2 sqrt(3) + 3
= (2 + sqrt(3))^2
Now, since
√x + 1/√x = (x + 1) / sqrt(x),
Substitute 7 + 4 sqrt(3) for x:
= (7 + 4 sqrt(3) + 1) / sqrt(7 + 4 sqrt(3))
Collect terms:
= ( 8 + 4 sqrt(3)) / (2 + sqrt(3))
Factor the numerator:
= 4 [ ( 2 + sqrt(3) ) / (2 + sqrt(3)) ]
= 4 (1)
= 4
7 + 4 sqrt(3)
= 4 + 2 sqrt(3) + 2 sqrt(3) + 3
= (2 + sqrt(3))^2
Now, since
√x + 1/√x = (x + 1) / sqrt(x),
Substitute 7 + 4 sqrt(3) for x:
= (7 + 4 sqrt(3) + 1) / sqrt(7 + 4 sqrt(3))
Collect terms:
= ( 8 + 4 sqrt(3)) / (2 + sqrt(3))
Factor the numerator:
= 4 [ ( 2 + sqrt(3) ) / (2 + sqrt(3)) ]
= 4 (1)
= 4
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