Question

guys please tell me this answer. 4th question all parts​

Answer 1

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Explanation:

GIVEN:

Object size[h]=3cm

Object distance=10cm

Image size[h']=4.5cm

1.Magnification of concave mirror[m]:

m=-v/u=h'/h

m=4.5/3

m=1.5D

2.The magnification produced have a positive value.

3.The value of image distance [v] and object distance [u] is:

m=-v/u

1.5=-v/10

-v=15

v=-15 cm

Where, negative sign indicates that image is inverted

4.What is the focal length of mirror [f]:

f=uv/u+v

f=10*(-15)/10+15

f=-150/25

f=-6cm

5.The nature of image formed by mirror:

The image is magnified, inverted and virtual