Physics, asked by Anonymous, 7 months ago

guys plez answer this question.....​

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Answered by rishavpaul503
3

Answer:

Initial energy E=1/2 CV square

E=1.2*10 {to the power, (-5)} J

when another capacitor is connected

1/C {suffix 1} = 1/C + 1/C

C {suffix 1} = 300 pF

E {suffix 1} = 1/2 C {suffix 1} V2 = 0.6*10 {to the power, (-5)}

E = E - E {suffix 1} = 6*10 {to the power -6} J

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