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A cuboidal box of dimensions 1 m × 2 m × 1.5 m is to be painted except its bottom. Calculate how much area of the box has to be painted.
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Answer:
Given,
Length of the box, l = 2 m,
Breadth of box, b = 1 m
Height of box, h = 1.5 m
We know that the surface area of a cuboid = 2(lb + lh + bh)
But here the bottom part is not to be painted.
So,
Surface area of box to be painted = lb + 2(bh + hl)
= 2 × 1 + 2 (1 × 1.5 + 1.5 × 2)
= 2 + 2 (1.5 + 3.0)
= 2 + 9.0
= 11
Hence, the required surface area of the cuboidal box = 11 m²
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