Math, asked by Agil1, 1 year ago

guys pls answer these tomorrow is my school

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Answered by aishowrya
0
Heya!

Here's your answer! ^^

1. Let the number of pants purchased be x
And skirts purchased be y.

Then the number of skirts purchased = 2 × (no. of pants purchased) - 2
=> y = 2x - 2
=> 2x - y - 2 = 0 (i)

Also, the no. of skirts purchased = 4 × (no. of pants purchased) - 4
=> y = 4x - 4
=> 4x - y - 4 = 0 (ii)
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Solving (i),
2x - y - 2 = 0
=> y = 2x - 2

Let x = 1, then -
y = 2(1) - 2 \\  y = 2 - 2 \\ y = 0
So, x = 1, y = 0 is a solution

Now, let x = 2, then -

y = 2(2) - 2 \\ y = 4 - 2 \\ y = 2
So, x = 2, y = 2 is a solution too
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Solving (ii)

Let x = 1

Then, y = 4(1) - 4 = 0
So, (1, 0 ) is a solution

Let x = 2
y = 4 ( 2 ) - 4 = 4
So, (2, 4) is a solution too
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On plotting both the solutions on the graph,

Number of pants bought by champa = x = 1
Number of skirts bought by Champa = y = 0

Another solution of the same bit can be by subtracting equation (i) from (ii) too.

Hope it helps! ^^


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