Math, asked by kornu999, 15 days ago

guys pls answer this question ..it's very urgent​

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Answers

Answered by itzmecuterose
0

Answer:

Ok, first you're going to have to factor the function inside the log:

2x^2 +8x+8, you can use the quadratic formula and you'll get these factors:

(2x+4)(x+2)

Now you have log2 ((2x+4)(x+2))

When you have multiplication inside logs that is equal to sdding logs

log2(2x+4) + log2 (x+2)

Now from the first part you can factor out a 2

2(x+2)

log (2) + log (x+2) + log (x+2)

And that's as far as it can expand

Answered by priyanshusrinivas
0

([3/4)^-2 +(4/5)^-3](3/5)^-2

=[(4/3)^2+(5/4)^3](5/3)^2

=[9/4+125/64](25/9)

=[144+125/64](25/9)

=[269/64](25/9)

=[6725/576]

Step-by-step explanation:

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