Question

guys pls do answer it's urgently​ needed pls guys
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Answer 1

Answer:

=>(n!)÷[2! * (n-2)!] = (n!)÷ [3! * (n-3)!]

=> 1 by 2 * (n-2)(n-3)(n-4).... = 1 by 6 * (n-3)(n-4)(n-5).....

=> 1 by n-2 = 1 by 3

=> n-2 = 3

=> n = 5

hope it helps

plz mark it the brainliest