Question

guys pls help me.......

answer me..........

I will mark your answer as brainlist.

the answer is 16 days.

please give me answer with explanation.

A can do a work in 45 days . he works at it for 15 days and then , B alone finishes the remaining work in 24 days. find the time taken to complete 80 % of the work if they work together.​

Answer 1

Answer:

A alone can do work in 1 day =1/45

B =1-1/x=24

1x-1=24x

24x-1x=44x=1/23

A and B together one day work =1/45+1/23

Step-by-step explanation:

after that you can solve

Answer 2

Step-by-step explanation:

The time taken to complete 80% of the work if A & B work together is 16 days.

Step-by-step explanation:

A alone can do a work in 45 days

So, work done by A in 15 days =  = 15/45=1/3

∴ Remaining fraction of work that is done by B alone = 1 - = ← in 24 days

∴ The whole work will be done by B alone in = 24 × 3/2 = 36 days

Now,  

Work done by A in 1 day = 1/45

Work done by B in 1 day =   1/36

∴ Work done by A and B together in 1 day is given by,

=   1/45+1/36

=   5+4/180

=   9/180

=   1/20

If, 1 whole work is done by A and B together in 20 days.

Then, 80% of the work will be done in = 20 * 4/5 = 16 days