Guys pls help me to solve this problem.I need a clear explanation guys
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hey!!
here is your answer >>>
angle DBC = In the middle of the star , we can find an angle named X, If we find that angle, we can find the angle DEF!. That angle x is inscribed inside a pentagon!. This pentagon has all the sides equal, according to the question!. Now let us find the angle x.
The total angle of a pentagon is 540° ..
how? > The formula to find the total angle is
(n - 2) 180!.
n is the number of sides!.
Pentagon has 5 sides!. .
(5-2)180
3(180)
=> 540° ..
As all sides are equal, each angle too would be equal.
To find x , we will have to divide 540 by 5!.
540/5
=> 108°!.
Then angle DBC would be 180-108
=> 72°!. (straight angle).
Now, angle DEF
As we know, each angle of a pentagon is 108°.
BDF and HFD would also be 108°>>>
Then, DFE and FDE would be 72° (straight angle ). Angle DEF would be
180-(72+72)
180- 144
36°!.
As the total sum of angles in a triangle is 180°!.
I guess the geometric name of a start is star polygon!.
Hope my answer helps!
here is your answer >>>
angle DBC = In the middle of the star , we can find an angle named X, If we find that angle, we can find the angle DEF!. That angle x is inscribed inside a pentagon!. This pentagon has all the sides equal, according to the question!. Now let us find the angle x.
The total angle of a pentagon is 540° ..
how? > The formula to find the total angle is
(n - 2) 180!.
n is the number of sides!.
Pentagon has 5 sides!. .
(5-2)180
3(180)
=> 540° ..
As all sides are equal, each angle too would be equal.
To find x , we will have to divide 540 by 5!.
540/5
=> 108°!.
Then angle DBC would be 180-108
=> 72°!. (straight angle).
Now, angle DEF
As we know, each angle of a pentagon is 108°.
BDF and HFD would also be 108°>>>
Then, DFE and FDE would be 72° (straight angle ). Angle DEF would be
180-(72+72)
180- 144
36°!.
As the total sum of angles in a triangle is 180°!.
I guess the geometric name of a start is star polygon!.
Hope my answer helps!
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