Math, asked by MISBAH9999, 10 months ago

guys pls help me with it​

Attachments:

Answers

Answered by prashika642018
0

Answer:hey there is ur answer

a=-1

B=√2

Attachments:
Answered by niharikam54
1

Answer:

Given polynomial is x^3-3x^2 +x+1

By comparing it with a x^3+bx^2+cx+d

a = 1 , b=-3 c=1 , d =1

sum of the roots = a-b+a+a+b = -b/a

3a = 3

a =1

product of the roots = a (a-b) (a+b) = c/a

a( a^2 - b^2 ) =1

1-b^2 =1

b =0

the value of a = 1 , b= 0

hope this helps you.Mark me as BRAINLIEST if you got the correct answer

Similar questions