guys pls help me with it
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Answer:hey there is ur answer
a=-1
B=√2
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Answer:
Given polynomial is x^3-3x^2 +x+1
By comparing it with a x^3+bx^2+cx+d
a = 1 , b=-3 c=1 , d =1
sum of the roots = a-b+a+a+b = -b/a
3a = 3
a =1
product of the roots = a (a-b) (a+b) = c/a
a( a^2 - b^2 ) =1
1-b^2 =1
b =0
the value of a = 1 , b= 0
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