guys pls help me with these problems
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Given : AB||CD
angle ABO = 135°
angle ODC = 145°
Construction : Draw a line segment BD is divide BDC is 90° .
Solution :
In ∆ OBD
angle BDO = 145°-90° = 55°
angle DBO = 135° -90° = 45°
we know that sum of ∆ angles is = 180°
so ,
angle BDO + DBO +BOD = 180°
55 ° +45° + BOD = 180°
BOD = 180° - 100°
BOD = 80°
so, the value of x = 80°
angle ABO = 135°
angle ODC = 145°
Construction : Draw a line segment BD is divide BDC is 90° .
Solution :
In ∆ OBD
angle BDO = 145°-90° = 55°
angle DBO = 135° -90° = 45°
we know that sum of ∆ angles is = 180°
so ,
angle BDO + DBO +BOD = 180°
55 ° +45° + BOD = 180°
BOD = 180° - 100°
BOD = 80°
so, the value of x = 80°
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