Physics, asked by aarchitad13405, 1 year ago

Guys... Pls help me with this question with an explanation:

The amount of work done in stretching a spring of force constant 500N/m to form a stretched length of 40 cm to 50 cm is __________ .

a)45 J b)22.5 J c)45 x 10^{4} d)22.5 x 10^{4}

Answers

Answered by harleenrani8684
0

Answer:

ANSWER IS (a) 45 J

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