Question

guys pls solve 3rd question.without solving find the value of p when given equation has equal roots. ​

Answer 1

Answer:

The equation have equal roots when ,

${b}^{2} - 4ac = 0$

So ,

Applying this in this equation, where

A = (p-3)

B = 2(p-3)

C = 2

We get ,

$= {b}^{2} - 4ac = 0$

$= {(2(p - 3))}^{2} - 4(p - 3)(2) = 0$

$= {(2p - 6)}^{2} - 4(2p - 6) = 0$

$= {4p}^{2} + 36 - 24p - 8p + 24 = 0$

$= {4p}^{2} - 32p + 60 = 0$

${p}^{2} - 8p + 15 = 0$

Splitting middle term ,

${p }^{2} - (5x + 3x) - 15 = 0$

$= {p}^{2} - 5x - 3x + 15 = 0$

$= p(p - 5) - 3(p - 5) = 0$

$= (p - 3)(p - 5) = 0$

So ,

p = 3 , 5

Hope it helps you:)