Question

guys pls solve it,if u gave correct answer I will follow u.....​

Answer 1

Answer:

as we know that

R = rho(l/A)

therefore the initial resistance was rho(l/A)

After changing the new resistance is

R= ¶ (1/3l/2A) here ¶ is equal to rho

R =¶(l/6A)

on comparing we find that the new resistance is 1/6 of the initial resistance.

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Answer 2

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Please refer to the attachment fir solution.

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