Math, asked by saiaashish, 1 year ago

guys pls solve this q3

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Answers

Answered by Saloni001

log 2
!!! is ans
LIKE IT

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saiaashish: hiw to solve elimination????

saiaashish: i dont know

Answered by siddhartharao77

The answer is option(A).

Hope it helps!

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saiaashish: ls

saiaashish: pls

saiaashish: ay

saiaashish: how it is log 2

siddhartharao77: (2^28 * 3^12 * 5^10)/(2^27 * 3^12 * 5^10). Common values will be cancelled like 3^12 and 5^10. Only 2^28/2^27 will be left. 2^28 can be written as 2^27 * 2^1/ 2^27 = 2^27 will be cancelled. 2^1 will be left. That means 2^1 = 2

siddhartharao77: Therefore will be log(2).

saiaashish: ok bro

saiaashish: tq

saiaashish: can u solve some other too

saiaashish: pls

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