Question

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√(151)^2 + (160.3)^2​

Answer 1

Step-by-step explanation:

= 151 + 25696.09

= 25847.09

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Answer 2

Let x=greater number

y= lesser number=19+ x^1/2. Equation 1

x+y= 151. Equation 2

x+19+x^1/2=151, x+x^1/2=151–19= 132

x^1/2=132-x , squaring both sides,

x=17424–264x+x^2

x^2–265x+17424=0

By quadratic equation solution for x:

x={265+-[(265)^2–4(1)(17424)]^1/2}/2

x=265+-(529)^1/2

x=(265+23)/2 and x=(265–23)/3

x=144 and x=121

Try x=144

144+y=151

y=151–144=7

y=19+(144)^1/2=19+12=31 not ok because y from Eq. 2 is not equal to y from Eq. 1.

Try x=121

121+y=151

y=151–121=30

y=19+(121)^1/2=19+11=30 OK

Conclusion:

x=121 greater number

y=30 lesser number

Sum of x+y=121+30=151 ok

y=19+ square root of 121=19+11=30 ok

So the value of greater number minus the lesser number is 121–30=91

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