Question

Guys pls tell the answer with steps. plssss pls​

Answer 1

Answer:-

In ∆ABC ,

$\huge\sf\red {Given-}$

• ∠A = 60°

• ∠B = 45°

$\huge\sf\orange {To \: Find-}$

• ∠C = ?

$\huge\sf\pink{Formula \: to \: be \: used-}$

• Angle sum property of triangle-

∠A + ∠B + ∠C = 180°

$\huge\sf\purple {Solution-}$

Let the angle ∠C be x.

So, according to angle sum property

$\sf\orange { \implies ∠A + ∠B + ∠C = 180°}$

Now, put the values-

$\sf\blue {\implies 45° + 60° + x = 180°}$

$\sf\blue {\implies 105° + x = 180°}$

$\sf\blue {\implies x = 180° - 105°}$

$\sf\red {\implies x = 75°}$

$\huge {\boxed {\bf {\purple { x = 75°}}}}$

_________....

__________....

Verification-

We know-

$\huge\rm\pink {∠A + ∠B + ∠C = 180° }$

So,

$\sf\green{\implies 45° + 60° + 75° = 180°}$

$\sf\green{ \implies 105° + 75° = 180° }$

$\sf\green {\implies 180° = 180°}$

$\huge {\boxed {\bf {\purple { Hence \: verified!!! }}}}$

Answer 2

Given:-

Measurement of the angles of the triangle:- (2 angles)

• 45°
• 60°.

We know,

Sum of interior angles of a triangle = 180°

Let the third angle be = x

According to the Question:-

x + 45° + 60° = 180°

→ x + 105° = 180°

→ x = 180° - 105°

→ x = 75°.

So, the third angle was 75°.

Verification:-

LHS:-

x + 60° + 45°

= 75° + 105°

= 180°

RHS:-

180°

∴ LHS = RHS.