guys plse help me .i will follow u if u answer it.guys I need 2 and 3 solutions. can u do that small help for me. plse
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2) two triangles are similar
ratio of bases will be equal to ratio of altitudes
now ratio of both the triangles will be solved answer will come
4/9
ratio of bases will be equal to ratio of altitudes
now ratio of both the triangles will be solved answer will come
4/9
Answered by
2
if altitudes are in ratio 2:3 then corresponding sides are also in same ratio if
corresponding sides are in ratio 2:3 then the median are also in the same ratio.
if the corresponding sides are in ratio 2:3 then the their area are in the ratio 4:9
corresponding sides are in ratio 2:3 then the median are also in the same ratio.
if the corresponding sides are in ratio 2:3 then the their area are in the ratio 4:9
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AB^2=BD^2+AD^2
hence
AD^2=AB^2-BD^2 ---------------(1)
in the same way for ∆ACD
AD^2=AC^2-CD^2 -------------(2)
from equation (1) and (2)
2AD^2=(AB^2+AC^2)-(BD^2+CD^2)
but we know traingle is. equilateral
so,
AB=BC=CA
and BD=CD=BC/2
hence ,
AD=√3/2AB=√3/2BC =√3/2CA
(5) ∆ ABC~ ∆DEF
so ,
AB/DE=BC/EF=AC/DF
1/2 =8cm/EF
EF=16cm