guys plz answer my question.only correct answer needed.*WITH STEPS*
Answers
Step-by-step explanation:
9) Two co-interior angles are in the ratio 5:7
Let these angles be (5×x)° = 5x°and (7×x)°=7x° respectively
When two parallel lines are cut by a transversal then,
Sum of two co-interior angles = 180°
5x°+7x° = 180°
5x+7x = 180
12x = 180
x = 180/12
x = 15
The co-interior angles are
(5×15)°= 75°
(7×15)°=105°
10) We know that,
Sum of angles in a point = 360°
100°+46°+64°+x = 360°
100+46+64+x = 360
210+x = 360
x = 360-210
x = 150
The value of x is 150°
Answer:
9. If two lines are parallel, then co interior angles becomes supplementary to each other.
Let the angles be 5x and 7x, then 5x+7x = 180, so x = 15.
Hence required angles are 75 and 105.
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10. From the fig, clearly, 100+46+64+x = 360. So, x = 150
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11. On the line PQ, if angle POR = 90, then, since PQ is a straight line, angle POR + x + y = 180, so, x + y = 90.
Also, x:y = 3:2, so, x = 3/2y, which gives, 3/2y+y =90.
(b) Hence, y = 36.
(a) So, x = 54.
Now since lines PQ and ST intersect at O, so angle POS = y (vertically opposite angles)
(c) So, angle POS = 36
Similarly angle POT = angle SOQ
=> angle POR + x = z
(d) z = 90+36=126
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12. If p and q are parallel lines and n intersect them, then 4z = 108 (corresponding angles)
So, z = 27
Similarly, l and m are parallel, so 3y=6x => y=2x
And l and n are parallel, 6x = 108
So, x = 18
And y = 36
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13. If PQ || ST, then x = 85 (alternate angles)
On line PQ, clearly, 130+y = 180
So, y = 50
Hence, x+y = 135
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14. If PQ || RT, then, x = 70 (alternate angles)
Again, in triangle PQR, x + y + 30 = 180
So, y = 80
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I hope it helps