Question

guys plz do answer me for the 2nd question.... irrelevant answers will be reported on the spot....​

Answer 1

Step-by-step explanation:

hope it helps u ..........

Answer 2

Method 1 ⇒ Factorization

Let's solve your equation step-by-step

$x^{2} +5x-6=0$

Step 1: Factor left side of equation.

⇒ $(x-1)(x+6)=0$

Step 2: Set factors equal to 0.

⇒ $x-1=0 \ or \ x+6=0$

⇒ $x=1 \ or \ x=-6$

$\rule{300}{1}$

Method 2 ⇒ Using Quadratic Formula

Let's solve your equation step-by-step.

$x^{2} +5x-6=0$

For this equation: a=1, b=5, c=-6

⇒ $1x^{2}+5x+-6=0$

Step 1: Use quadratic formula with a = 1, b = 5, c = -6.

⇒ $x=\dfrac{-b\± \sqrt{b^{2}-4ac} }{2a}$

⇒ $x=\dfrac{-(5)\±\sqrt{5^{2}-4(1)(-6)} }{2(1)}$

⇒ $x=\dfrac{-5\±\sqrt{25-4(-6)} }{2}$

⇒ $x=\dfrac{-5\±\sqrt{25-(-24)} }{2}$

⇒ $x=\dfrac{-5\±\sqrt{49} }{2}$

⇒ $x=\dfrac{-5\± 7 }{2}$

⇒ $x=1 \ or \ x=-6$

$\rule{300}{1}$

$\bf \therefore x=1\ or \ x=-6 \ in \ the \ equation => \ x^{2} +5x-6=0$

$\rule{300}{1}$