Question

guys plz do solve this math problem..... plzz....​

Answer 1

Answer:

Given

In ∆ ABC

• AB=AC
• angle A= 80°

To find

value of angle B

Solution

In∆ ABC

side AB= Side AC [given]

This means ∆ ABC is a isosceles triangle.

⛦According to the property of isosceles triangle the angles of adjoing equal sides are also equal.

$\sf{ \therefore \: \angle \: B = \angle \: C}$

⛦ The sum of interior angles in a triangle is 180°.

Let us assume angle B and angle C as x°

$\sf{ \implies \: \angle a + \angle \: b + \angle \: c = 180 \degree} \\ \\ \sf{ \implies \: 80 + x+ x = 180 \degree } \\ \\ \sf{ \implies \: 80 \degree + 2x = 180 \degree} \\ \\ \sf{ \implies2x = 100} \\ \\ \sf{ \implies \: x = \frac{100}{2} = 50 \degree}$

Therefore the value of angle B is 50°.

Answer 2

Answer:

angle B = 50°

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Step-by-step explanation:

As AB= AC

angle B = angle C = x (say) (angle opposite to equal sides are equal)

angle A + angle B + angle C = 180°

80° +2x= 180°

2x = 180°-80° = 100°

X= angle B= 50°