Guys Plz heIIp me I w¡ll do anyth¡ng if U heIp me Plezeee
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You have to see this way:
Across AB (3 ohm), the resistance 2 and 5 are in series, =7. This 7 is in parallel to AB 3 ohm
Rab=3+1/{(1/2)+(1/5)}=3+1/(7/10)=3+10/7=31/10
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