Guys plz help me in this question plz....
If tan9Φ=cotΦand 9Φ<90°,then find the value of cosec5Φ.
guys, it's just a 1 mark question. answer this... plz
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tan9Ф= cotФ
tan9Ф= tan(90-Ф)
9Ф=90-Ф
10Ф=90
Ф=9°
cosec 5Ф = cosec 5(9)
cosec 45° =√2
tan9Ф= tan(90-Ф)
9Ф=90-Ф
10Ф=90
Ф=9°
cosec 5Ф = cosec 5(9)
cosec 45° =√2
riya2234:
thanks
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