Question

guys plz help me l am asking this question for the third time
plz don't give irrelevant answers.
a pipe open at both ends has fundamental frequency 450Hz is filled with water upto 3/4 of its length what is new frequency ​

Answer 1

Explanation:

Let velocity of sound in air be v.

Open organ pipe:

Let Length of the pipe be L.

Fundamental frequency i.e m=1, ν

1

=n=

2L

v

When the pipe is immersed in water, it acts like a closed organ pipe.

Length of the air column, l=

2

L

Frequency of different modes in closed organ pipe, ν

p

′

=

4l

(2p−1)v

Fundamental frequency i.e p=1 , ν

1

′

=

4×

2

L

v

=

2L

v

=n

please mark as brainlist answer