guys plz help me pass this test plz plz plz
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Solution:
First factor out the GCF.
f(x) = x^4 + 4x^3 - 21x^2
All the terms have at least x^2.
x^2(x^2 + 4x - 21)
Then factor the trinomial
x^2(x + 7)(x - 3)
Then set each factor equal to zero.
x^2 = 0 (which is x = 0, x = 0)
x + 7 = 0, x - 3 = 0
Then solve for all the x's
So x = 0, x = 0, x = -7, x = 3.
Therefore, a = 0, a = 0, b = -7, c = 3
a^2 + b^2 + c^2 = 0 + 49 + 9 = 58
Hope this will be helpful.
First factor out the GCF.
f(x) = x^4 + 4x^3 - 21x^2
All the terms have at least x^2.
x^2(x^2 + 4x - 21)
Then factor the trinomial
x^2(x + 7)(x - 3)
Then set each factor equal to zero.
x^2 = 0 (which is x = 0, x = 0)
x + 7 = 0, x - 3 = 0
Then solve for all the x's
So x = 0, x = 0, x = -7, x = 3.
Therefore, a = 0, a = 0, b = -7, c = 3
a^2 + b^2 + c^2 = 0 + 49 + 9 = 58
Hope this will be helpful.
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