Question

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40 ml of HCL is exactly neutralised by 20 ml of NAOH sol.The resulting neutrelised solution is evaporated to dryness and the
residue is found to have a mass of 0.117 g Calculate the
normality of HCL and NaOH sol.​

Answer 1

Answer:

hcl + Naoh = NaCl +H2O

N of HCl = 40/36.5 into 1000/40 = N= 1(approx.)

N of NaOH = 20/40 into 1000/20= N=2.5

Explanation:

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