Question

guys plz solve question no-2 and 3...plz guyz its urgent ....plz fast ...i request u....

Answer 1

2.
Let the unknown angles be 5x & 7x.
Sum of all angles of quadrilateral is 360°.
68°+76°+5x+7x = 360°
144°+12x = 360°
12x = 216°
x = 216°/12
x = 18°

Therefore, the angles are 5(18)=90° & 7(18)=126°.

3.
4x+5x+10+7x-20+6x+18 = 360°
22x+8 = 360°
22x = 360°-8
22x = 352
x = 16°

All angles are,
4x = 64°
5(x+2) = 90°
7x-20 = 92°
6(x+3) = 114°

Answer 2

2. Let 1 angle = 5x
and other = 7x
A.T.Q
7x+5x+68+76=360 degree(angle sum property)
12x+144=360
12x=360-144
x=216÷12
x=18
so 1st angle = 5x=5×18=90
2nd angle = 7x=7×18=126


3. 1st angle=4x
2nd angle=5 (x+2)
3rd angle =(7x-20)
4th angle = 6(x+3)
A.T.Q
4x+5x+10+7x-20+6x+18=360 (angle sum property)
22x+8=360
22x=360-8
x=352/22
x=16
so find all angles by putting value of x