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Answer:
Given :-
108a²-3 (b-c)²
Taking 3 as common in the given question
108a²-3 (b-c)² =3[36a²-(b-c)²]
We can write it as
108a²-3 (b-c)² =3[(6a)²- (b-c)²]
Based on the equation a²-b² =(a+b)(a−b)
We get,
108a²-3 (b-c)² =3(6a+b−c)(6a−b+c)
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