Physics, asked by Anonymous, 3 months ago

Guys plz solve this.

108a^{2} −3(b−c)^{2}


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Answers

Answered by Rizakhan678540
5

Answer:

Given :-

108a²-3 (b-c)²

Taking 3 as common in the given question

108a²-3 (b-c)² =3[36a²-(b-c)²]

We can write it as

108a²-3 (b-c)² =3[(6a)²- (b-c)²]

Based on the equation a²-b² =(a+b)(a−b)

We get,

108a²-3 (b-c)² =3(6a+b−c)(6a−b+c)

Answered by jitenderthakur34
0

I hope it helps. u dear.

answer in the attachment .

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