Guys plzz help me with this question it's very important!!!
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Answer:
∠ACD = 35°
∠ABD = 75°
Step-by-step explanation:
∠BDA = 70°
so ∠CDA = 110° (linear pair of angle)
∆CAD = ∠ACD + ∠DAC + ∠ADC = 180° (sum of all angles of the triangle)
∠ACD = ∠DAC = 35° (AD = AC; which makes ∆CAD as isosceles triangle)
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EKK TOH MAINE TUM PRR VISHWAS KRR KE TUMHE FOLLOW KIYA PRR TUMME TOH UNFOLLOW KRR KE DALLA PANTI DIKHADI......xD
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TUM JAISO PRR TOH VISHWAS HI NHI KRNA CHAHIYE
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₣ʉ₵₭ ø₣₣
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