guys plzz tell me the right answer of this ques. I am very confused
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lemme help u...
the hexagon is divided into different parts in which there are 2 ∆'s, 1 sq. and 1 trapezium.
so,
area of sq.= Side²
= 4²
= 16cm²
area of ∆ABC = ½ × base × height
= ½ × 8 × 5
= ½ × 40
= 20cm²
area of ∆(2) = ½ × base × height
= ½ × 6.2 × 4
= ½ × 24.8
= 12.4cm²
area of trapezium = 2(sum of ll sides)/base
= 2(10.2 + 8.4)/4
= 18.6/ 2
= 9.3cm²
total area = 16 + 20 + 9.3 + 12.4
= 36 + 21.7
= 57.7 cm²
hope it helps...
please mark this answer as brainliest if it was helpful
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