Question

...... guys plzzz do solve this math problems.... plzz​

Answer 1

$\huge{\pink{\underline{\underline{\bf{AnSweR:}}}}}$

i) Angle PBA + Angle PMC = 180°

(Linear Pair)

$→\;{\sf{120°+Angle\;PMC = 180°}}$

$→\;{\sf{Angle\;PMC = 180°-120°}}$

$◕➜\;{\red{\bf{Angle\;PMC = 60°}}}$

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ii) Angle PBA = Angle CMQ

(Vertically Opposite Angles)

$◕➜\;{\green{\bf{Angle\;CMQ = 120°}}}$

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iii) Angle PMC = Angle MQR (Corresponding Angles)

$◕➜\;{\purple{\bf{Angle\;MQR = 60°}}}$

Hope It Helps You ✌️