Question

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Answer 1

Answer:CaCO3 + 2HCl → CaCl2 + CO2 + H2O

This equation tells you that for every mol of CaCO3 consumed you will be producing 1 mol of CO2. In other words there is a 1:1 relationship between CaCO3 and CO2.

The next step is to determine the amount of CaCO3 you have in moles, and since HCl is in excess, you do not need to worry about which one is the limiting reagent (CaCO3 is limiting since HCl is in excess)

Answer 2

Na2CO3+2HCl---------->2NaCl+CO2+H2O

Molecular weight of Na2CO3=106

Molecular weight of HCl =36.5

1 mole of CO2 is produced from 106gm Na2CO3

0.1 mole of CO2 is produced from

=106×0.1

=10.6 gm

Hope It Helps!