guys question number 11 please please please please please please please please please please tell me by 9:30 pm
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angle ACB is 30°
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angle ACB = 30°
first we make the construction
The joint AE such that it become parallel to BC
then ABCE is a parallelogram
then angle ACE = angle CAB ( alternate interior angles)
Angle ACE =ANGLE CAB =70°
WE ALSO KNOW THAT SUM OF ALL ANGLES OF TRIANGLE IS 180°
SO IN TRIANGLE ABC
ANGLE A+ANGLE B+ANGLES C= 180°
70°+80° +ANGLE C = 180°
ANGLE C= 180°-150°
ANGLE C= 30°
THUS ,ANGLE ACB=30°
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