Question

guys quick help me with this^​

Answer 1

$2x - y = 14 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm \cdots(i)\\ 3x + 2y = 70\: \: \: \: \: \: \: \: \: \: \: \: \: \rm \cdots(ii)$

From Equation (i), we have,

$\large{}y = 2x - 14 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm\cdots(a)$

Putting Equation a in Equation (ii), we get,

$= > 3x + 2(2x - 14) = 70 \\ = > 3x + 6x - 28 = 70 \\ = > \: \: \: \: \: \: 9x - 28 = 70 \\ = > \: \: \: \: \: 9x = 70 + 28 \\ = > \: \: \: \: \: \: \: 9x = 98 \\ \\ = > \: \: \: \: \: x = \frac{98}{9} \\ \\ = > \: \: \: \: \: \: x = 10 \frac{8}{9}$

And,

$\text{Value of y} = 2x - 14 \\ \\ = > 2 \bigg\{ \frac{98}{9} \bigg\} - 14 \\ \\ = > \frac{196}{9} - 14 \\ \\ = > 14\bigg( \frac{14}{9} -1 \bigg) \\ \\ = > 14\bigg( \frac{14 - 9}{9} \bigg) \\ \\ = > 14\bigg( \frac{5}{9} \bigg) \\ \\ = > \frac{70}{9} \: \: \: \rm{}or \: \: \: 7\frac{7}{9}$

Thus,

$\boxed{x = \frac{98}{9} \: \: \: \rm{or} \: \: \: 10 \frac{8}{9} } \\ \\ \\ \boxed{y = \frac{70}{9} \: \: \: \rm{or} \: \: \: 7 \frac{7}{9} }$

Answer 2

Answer:

tokkk

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