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solution please ❗❗
QNO:46
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Answers
↪Actually welcome to the concept of the MOLARITY OF MIXED OR DILUTE SOLUTIONS
↪Basically for this type of misicible solutions
we use the following result to calculate the final MOLARITY
↪thus we use as
↪MOLARITY = (M1V1 + M2V2) ÷ V1 + V2
↪But obvious, the water had Zero MOLARITY at STP , so it's M = 0
↪so after solving we get as
〽M of the final diluted solution = 0.3125 M
of course the country and experience to work with your earliest response from your answer best regards tex version is a very happy witin ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
in ∆ABC if cosA cosB cosC=1/3 then TanA TanB+TanB TanC+TanC TanA=A race horse runs straight north and covers a distance of 12 m, then turns east and travels a distance of 5 m. Draw the diagram showing the displacements
and from the figure, calculate the net displacement of the horse.
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