guys solution plz immediately
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Step-by-step explanation:
sec²A+tan²A=5/3
sec²A+sec²A-1=5/3 [1+tan²A=sec²A]
2sec²A=5/3 -1
sec²A =2/3×2
sec²A =1/3
secA =1/√3
tanA= 2/√3
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