Math, asked by yadavsantoriya, 9 months ago

guys solution plz immediately

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Answered by Sara1305

1

Step-by-step explanation:

sec²A+tan²A=5/3

sec²A+sec²A-1=5/3 [1+tan²A=sec²A]

2sec²A=5/3 -1

sec²A =2/3×2

sec²A =1/3

secA =1/√3

tanA= 2/√3

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