Question

Guys solve thi question ....​

Answer 1

Answer:

Draw a circle with any radius and center O. Let AO and BO be the 2 radii of the circle and let AB be the chord equal to the length of the radius. ... Draw 2 points C and D on the circle such that they lie on the major arc and minor arc, respectively. Since ∆ABO is an equilateral triangle, we get ∠AOB = 60

Answer 2

Consider the figure.

Given,

AB is equal to the radius of the circle.

In △OAB,

OA=OB=AB= radius of the circle.

Thus, △OAB is an equilateral triangle.

and ∠AOC=60°.

Also, ∠ACB=21∠AOB=21×60°=30°.

Since, ACBD is a cyclic quadrilateral,

∠ACB+∠ADB=180° ....[Opposite angles of cyclic quadrilateral are supplementary]

⇒∠ADB=180°−30°=150°.

Thus, angle subtend by the chord at a point on the minor arc and also at a point on the major arc are 150° and 30°, respectively.