Question

guys solve this
class 11
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Answer 1

Hope it's helpful to you.

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Answer 2

Answer:

HI MATE.

First series is {1,4,7,10,13,..}

Second series is {2,7,12,17,.}

Third series is {3,10,17,24,}

See the least number in the third series which leaves remainder 1 on dividing by 3 and leaves remainder 2 on dividing by 5.

⇒52 is the least number of third series which leaves remainder 1 on dividing by 3 and leaves remainder 2 on dividing by 5

Now, A=52

D is L.C. M. of (3,5,7)=105

⇒A+D=52+105=157.

Hope it helps you mate.

please thank and mark my answer as brainliest.

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@ ANUSHA ❤✌