Guys.. Solve this question..
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Step-by-step explanation:
if x-1 is a factor of (×^10-1) than x=1 will satisfy this eqiation
put ×=1
(1^10-1)=0
same for (x^11-1)
3.
if (x-2), x+3, x-7 are the factor of eq. than it will satisfy eq
put x= 2 in eq. x^3-6x^2-13x+42
8-6×4-13×2+42
50-24-26=0
put x =-3
-27-6×(-3)^2-13×(-3)+42
15-54+39=0
put x = 7
343-6×49-13×7+42
385-294-91=0
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