Question

guys tell this answer​

Answer 1

Answer:

Step-by-step explanation:

$x = \frac{\sqrt{a + 1} + \sqrt{a - 1}}{\sqrt{a + 1} - \sqrt{a - 1} }$ $= \frac{(\sqrt{a+1}+\sqrt{a-1})^2}{a+1-a+1} = \frac{a+1+a-1 + 2\sqrt{a^2 - 1} }{2}$

$x = \frac{2a + 2\sqrt{a^2 - 1} }{2}$$= a+ \sqrt{a^2 - 1}$ -------(1)

Now square on both sides

x² = (a + √(a² - 1))² = a² + a² - 1 + 2a√(a²-1) = 2a(a + √(a²-1)) - 1 --- (2)

sub equation 1 in 2

x² = 2ax -1

x² - 2ax + 1 = 0

hence proved

Answer 2

Answer:

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