guys the ink I had written is the remaining part of 8th question pls tell me it's urgent
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♣︎Correct Question ♣︎
In ∆ABC;
- AB = BC
- AD is bisector of ∠BAC.
➹ Solution ➹
In ∆ABD and ∆ACD
- AB = BC [ Given ]
- AD = AD [ Given ]
- ∠BAD = ∠CAD [ AD is bisector of ∠BAC ]
Hence ; ∆ABD ≅ ∆ ACD
※To Prove :-
∠B = ∠C & BD = CD
※Proof :-
As ∆ABD ≅ ∆ ACD ;
Hence ;
∠B = ∠C [ By CPCT ]
BD = CD [ By CPCT ]
CPCT :- Corresponding Parts Of Congruent Triangles.
I HOPE IT HELPS.
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