Guys this is a tricky one. so the correct answer will be marked as brainliest.
prove that 0/0=2.
Answers
Answer:
Any division by zero is undefined but
0/0 is different from nonzero number/0
because if a is not zero and we try to
write x= a/0 , if it were definable then it
would satisfy
0x = a
and there is no such x.
However,
if a=0
the equation
0x =0 is true
for EVERY REAL NUMBER, and is in fact true for EVERY COMPLEX NUMBER!!!
That is the reason we call it indeterminant instead of undefined.
The fact that it is indeterminant leads to some
interesting and wonderful results you get to
study at the second or third Calculus level.
In particular, if an expression f(x)/g(x) is of the
form where f(x) gets closer and closer to zero
and g(x) gets closer to zero as x gets closer to
some number, there is a rule for figuring out
what f(x)/g(x) gets closer to or approaches.
If g(x) gets closer and closer to zero as
x gets closer and closer to a number such
as 5, then at the calculus level we say
limit as x gets closer and closer to 5 of g(x)
equals zero. The expression 2x -10 is
an expression which gets closer and closer
to zero as x gets closer to 5. Likewise
f(x)=x² - 25 gets closer and closer to 0 as
x gets closer to 5.
Consider f(x)/g(x) = (4x² - 100)/(2x- 10)
If we let x get closer and closer to 5 we can
see that f(x)/g(x) gets closer, in form to 0/0 .
In a first calculus course, we would factor
the numerator
and figure it equals 4(x-5)(x+5) and denominator
equals 2(x-5)
and since (x-5)/(x-5) equals 1 for all x not equal to 5 we assume it stays equal to 1 as x gets closer to zero and cancel them, obtaining
f(x)/g(x) = 4(x + 5)/2 , substitute in 5 and
figure out that 4(x + 5)/2 gets closer and
closer to 4(10)/2 = 20 as x gets closer to 5.
The 2nd or 3rd calculus course lets you prove
that using L'Hôpital's Rule for 0/0 type expressions that
as f(x)/g(x) gets closer and closer to a 0/0
form as x gets closer to 5 then
the expression gets closer in value to
f'(x)/g'(x) called the ratio of the derivatives.
You will learn what a derivative is in Calculus
For this example it is 8x/2 and we evaluate
this at x=5 to show it has a value of 20 .
Here 0/0 equals 20. However it does not always
equal 20. It can equal ANY REAL NUMBER.
That's the reason we call it indeterminate
[ Value not determined]
rather than simply undefined where
[The value does not exists]