Question

GUYS THIS IS URGENT.NO SCAM.I will mark the brainliest answer


A particle is moving with a constant acceleration a=i-2j + 2k m/s² and instantaneous velocity
V = i +2j+2k m/s, then rate of change of speed of particle 2 second after this instant will be :
(A) 19/7 m/s2 (B) 19/3 m/s (c)3 m/s (D) None of these​

Answer 1

Answer:

3 m/s²

Explanation:

A particle is moving with a constant acceleration a=i-2j + 2k m/s²

=>  rate of change of speed of particle 2 second after this instant will be  also same  =i-2j + 2k m/s²

rate of change of speed of particle = √1² +(-2)² +(2)²

=√(1 + 4+ 4)

=√9

= 3 m/s²

Speed after 2 sec = i +2j+2k  + 2(i-2j + 2k)

= 3i -2j + 6k

= √3² + 2² + 6²

= √9 + 4 + 36

=√49

= 7 m/s