Question

Guyss ans this it's urgent plzz​

Answer 1

Answer:

Answer given below....

Step-by-step explanation:

$(4x+y-3z)^2\\=(4x)^2+y^2+(-3z)^2+2(4x)(y)+2(4x)(-3z)+2(y)(-3z)\\=16x^2+y^2+9z^2+8xy-24x-6yz$

Identity used:

$(a+b+c)^2\\=(a+b+c)(a+b+c)\\=a(a+b+c)+b(a+b+c)+c(a+b+c)\\=a^2+ab+ac+ab+b^2+bc+ac+bc+c^2\\=a^2+b^2+c^2+2ab+2ac+2bc$

In this case,

a=4x

b=y

c=-3z

Hope it helps!

<3

Answer 2

Step-by-step explanation:

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