Question

GUYSS❤
SOLVE THIS!! ITS VERY URGENT!!

THE NUMBER OF SHARES HELD BY A PERSON OF VARIOUS COMPANIES ARE AS FOLLOWS. FIND THE MEAN.

NUMBER OF SHARES
100-200
200-300
300-400
400-500
500-600
600-700

NUMBER OF COMPANIES
5
3
3
6
2
1​

Answer 1

Class -- Freq. -- xi --- fixi

100-200 | 5 | 150 | 750

200-300 | 3 | 250 | 750

300-400 | 3 | 350 | 1050

400-500 | 6 | 450 | 2700

500-600 | 2 | 550 | 1100

600-700 | 1 | 650 | 650

_____________________________

$\sf \: mean \: = \frac{ \sum \: fixi}{ \sum \: fi} \\ </p><p> \sf \: substituting \: values \: in \: formula \\ \sf \: mean \: = \frac{7000}{20} \\ \sf mean \: = \frac{700}{2} \\ \sf \: mean \: = 350$

Answer 2

Step-by-step explanation:

$\bf \huge \: \: Question\: \:$

GUYSS❤

SOLVE THIS!! ITS VERY URGENT!!

THE NUMBER OF SHARES HELD BY A PERSON OF VARIOUS COMPANIES ARE AS FOLLOWS. FIND THE MEAN.

NUMBER OF SHARES

100-200

200-300

300-400

400-500

500-600

600-700

NUMBER OF COMPANIES

5

3

3

6

2

1

_________________________________

$\bf \huge \: \: To \: Find \:$

THE MEAN.

NUMBER OF SHARES

100-200

200-300

300-400

400-500

500-600

600-700

NUMBER OF COMPANIES

5

3

3

6

2

1

_____________________________

$\bf \huge \: \: Solution \: \:$

Class -- Frequent$\bf \: -- x_{i }--- f_{i}u_{i} \:$

$\bf \red{Let A = 450 ..and ..C = 100}$

100-200 | 5 | 150 | -3 | -15 |

200-300 | 3 | 250 | -2 |-6 |

300-400 | 3 | 350 | -1 | -3 |

400-500 | 6 | 450-A | 0 | 0 |

500-600 | 2 | 550 | 1 | 2 |

600-700 | 1 | 650 | 2 | 2 |

_____________________________

$\bf \: mean \: = \frac{∑fiui}{∑fi}$

$\bf \:∑f_{i}u_{i }= 20$

$\bf \:∑f_{i }= 20$

$\bf \: using \: the \: step \: deviation\:method$

$\bf \:x = \frac{∑f_{i}u_{i}}{∑f_{i}}\times c$

Putting the value from formula:-

$\bf \:</u></strong><strong><u> \frac{ - }{x} = 450 + \frac{ - 20}{20} \times 100 \\ \\ </u></strong><strong><u>$

$\bf \</u></strong><strong><u>r</u></strong><strong><u>e</u></strong><strong><u>d</u></strong><strong><u>{</u></strong><strong><u>450 - 100 = 3</u></strong><strong><u>5</u></strong><strong><u>0</u></strong><strong><u>}</u></strong><strong><u>$

$\bf</u></strong><strong><u> </u></strong><strong><u> \: </u></strong><strong><u>\</u></strong><strong><u>therefore</u></strong><strong><u> </u></strong><strong><u> </u></strong><strong><u>$ the mean of the data is $\bf \red</u></strong><strong><u>{</u></strong><strong><u>3</u></strong><strong><u>5</u></strong><strong><u>0</u></strong><strong><u>}</u></strong><strong><u>.</u></strong><strong><u>$

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