Math, asked by snehxshxrmx21261510, 1 year ago

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Answered by Anonymous
3

Answer.

Q. find a and b ,

i) a+ 2b+2ai = 4+6i

comparing real and imaginary part

then we get,

a+2b= 4 .......... eq.(1)

and ,. 2a=6

a= 3 put in. eq.(1)

3+2b=4

2b= 1

b= 1/2 ,a=3

ii). (a- b)+(a+b)i= a+5i

comparing real and imaginary part

a- b= a

b=0

and ,. a+b= 5

a+ 0=5

a=5 ,b=0

iii). (a+b)(2+i)= b+1+(10+2a)i

we can write

2a+2b+ai+bi= b+1+(10+2a)i

2a+2b+ (a+b)i= b+1+(10+2a)i

comparing real and Imaginary part

2a+2b=b+1

2a+3b=1.........eq.(1)

and

10+2a=a+b

3a-b= -10........eq.(2)

eq.(1)+3×eq.(2)

we get ,

11a= -29

a= 29/11

put the value of a in eq.(1)

2×29/11+3b= 1

3b = 1-58/11

b = -47/3

hope it helps u

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