guysss plxx answer Q.3
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yarr very. .. easy. . .wait
8x+5y=9
3x+2y=4
It is clear that;
a1/a2≠b1/b2 a1/a2≠b1/b2
Hence, there will be unique solution for the given pair of linear equations.
Subtracting first equation from second equation, we get;
x+26y–x–20y=1180–1000x+26y–x–20y=1180–1000
Or, 6y=1806y=180
Or, y=30y=30
Substituting the value of y in first equation, we get;
x+20y=1000x+20y=1000
Or, x+20x30=1000x+20x30=1000
Or, x+600=1000x+600=1000
Or, x=1000–600=400x=1000–600=400
Hence, fixed charges = Rs. 400 and per day charges = Rs. 30
8x+5y=9
3x+2y=4
It is clear that;
a1/a2≠b1/b2 a1/a2≠b1/b2
Hence, there will be unique solution for the given pair of linear equations.
Subtracting first equation from second equation, we get;
x+26y–x–20y=1180–1000x+26y–x–20y=1180–1000
Or, 6y=1806y=180
Or, y=30y=30
Substituting the value of y in first equation, we get;
x+20y=1000x+20y=1000
Or, x+20x30=1000x+20x30=1000
Or, x+600=1000x+600=1000
Or, x=1000–600=400x=1000–600=400
Hence, fixed charges = Rs. 400 and per day charges = Rs. 30
samuu51:
fixed charges?
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