guyz..help me...8th amd 9th
Attachments:
Answers
Answered by
4
we have,
T2=14 and T3= 18
a+d=14...i) and. a+2d = 18....ii)
solve i) and ii);
a+2d= 18
a+ d = 14
______________
d=4 and a= 10.
S51 = n/2(2a+(n-1)d)
= 51/2(2*10+(51-1)4)
= 51/2(20+200)
= 51/2(220)
= 51* 110
= 5610. Ans.
sureshsharma4084:
put the the value of a+d = 14 and get the value of d
a+2d= 18 => a+d+d=18 => 14+d= 18 => hence, d= 4.
ohh..tnx a lott
ohh god
finally u understand
hehe...
nice explanation
thanks dude
ur welcome
ok
Answered by
14
image attached to your answer if like please thank my answer ❤❤
Attachments:
take care dear
bye take care ^.^
hey stupid don't say ridiculous things
you ho to hell!!
go to hell
hii
what
Similar questions