Math, asked by radhika4086, 1 year ago

guyz plz solve 3rd 4th 5th 6th sums

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Answered by srini8381
1
3) Let the radius of the circle is r

Now diameter of the circle = 2r

The circumference of the circle = 2πr

Now according to question,

     2πr = 2r + 75

=> 2πr - 2r = 75

=> 2r(π - 1) = 75

=> 2r(22/7 - 1) = 75

=> 2r(22 - 7)/7 = 75

=> 2r(22 - 7) = 75*7

=> 2r*15 =  75*7

=> 2r =  (75*7)/15

=> 2r =  5*7

=> 2r = 35

=> r = 35/2

So, radius of the circle = 35/2 = 17.5 cm

and diameter of the circle = 2r = 2* 35/2 = 35 cm


srini8381: Hope it helps you
radhika4086: thnks baki bhi solve kr do
srini8381: In English
radhika4086: plz solve the 4th 5th 6 sum also
srini8381: tell in English
srini8381: wait
Answered by gegfhfhbduwobshakdbs
2

 \large \tt AHOY!!  \:

3. ATQ, the circumference of a circle exceeds it's diameter by 75cm.

let the radius of the circle be 'r'

we know that diameter is double of radius. therefore it's diameter is '2r'

now, it's given the circumference is 75cm more than it's diameter.

circumference of a circle = 2πr

=> 75 + 2r = 2πr

=> 75 = 2πr - 2r

=> 75 = r(2 × 22/7 - 2)

=> 75 = r(44/7 - 2)

=> 75 = r(44/7 - 14/7)

=> 75 = r(30/7)

=> 75/1 × 7/30 = r

=> 2.5 × 7 = r

=> r = 17.5cm

hence, the radius of the circle is 17.5cm

4. given radius of the circular field = 56m

we have to find the length of wire required to fence it two times.

so first of all, let's find the circumference of the circular field..

circumference of the circular field = 2πr

= 2 × 22/7 × 56

= 44 × 8

= 352m

since we have to fence it twice. multiply the circumference by 2.

hence, total length required to fence twice = 352 × 2 = 704m

5. given diameter :- 84m

therefore circumference of the circular garden = πd (u can also use 2πr by dividing diameter by 2 and u will get the radius)

= 22/7 × 84

= 22 × 12

= 264m

therefore total cost of the wire required @ rupees 10.85 = 264 × 10.85

= rupees 2864.4

6. circumference of inner track = 616m

therefore 2πr = 616m

=> 2 × 22/7 × r = 616m

=> 44/7 × r = 616m

=> r = 616/1 × 7/44

=> r = 14 × 7

=> r = 98

circumference of the outer track = 660m

=> 2πr = 660m

=> 2 × 22/7 × r = 660m

=> 44/7 × r = 660m

=> r = 660/1 × 7/44

=> r = 15 × 7

=> r = 105m

hence, width of the track = 105m - 98m

= 7m

HOPE THIS HELPS!!


radhika4086: i hv posted now sum
radhika4086: plz solve just now
gegfhfhbduwobshakdbs: ok
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