guyzzzzz.. help me out...
having xam tomorrow n still i din't get ans for ths...!!!!!!!!!!!!
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radius of the cone=6 cm
diameter=12 cm
height=8 cm
slant height²(l²)=h²+r²=64+36=100
l=10 cm
now look at the attached file....
we know the cone is like a triangle...find it's area and perimeter
s= half of perimeter
s=10+10+12/2=16 cm
area= 1/2 bh=1/2*12*8=48 cm²
radius of the sphere=
radius=
volume of the sphere=[tex] \frac{2}{3} \pi r^{3} \\ \\ \frac{2}{3}* \frac{22}{7} *3*3*3 \\ \\ =56.57 cm ^{3} [/tex]
change into liter=0.05657 liter will overflow...
2).
diameter=12 cm
height=8 cm
slant height²(l²)=h²+r²=64+36=100
l=10 cm
now look at the attached file....
we know the cone is like a triangle...find it's area and perimeter
s= half of perimeter
s=10+10+12/2=16 cm
area= 1/2 bh=1/2*12*8=48 cm²
radius of the sphere=
radius=
volume of the sphere=[tex] \frac{2}{3} \pi r^{3} \\ \\ \frac{2}{3}* \frac{22}{7} *3*3*3 \\ \\ =56.57 cm ^{3} [/tex]
change into liter=0.05657 liter will overflow...
2).
Revolution:
don't report my answer..i will do second qn too..after some time
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